[Ietf-not43] 3.2.4 Domain Information Lookup

[Jim Fleming]

With "experts" coaching the U.S. Government that the aging legacy root-servers can
only handle a small number of TLDs, because of bogus claims about attacks and over-load,
any new TLDs will have to displace existing TLDs. What TLDs would you remove ?

You might want to send the Whitehouse your suggested changes.
Whitehouse Ready to Release Next Generation Internet Plan

http://news.com.com/2100-1023-958159.html?tag=politech
http://www.politechbot.com/p-03994.html
http://www.uscryptomail.org/cybersecurity/

Note: The new plan calls for the same architecture used with IPv8 and IPv16,
whereby, users do not have direct access to the (out-of-band) IPv16 network.


----- Original Message ----- 
From: "Paul Stahura" <stahura@enom.com>
To: "'Andrew Newton'" <anewton@verisignlabs.com>; "Rick Wesson" <wessorh@ar.com>
Cc: <ietf-not43@lists.verisignlabs.com>
Sent: Wednesday, November 06, 2002 11:45 AM
Subject: RE: [Ietf-not43] 3.2.4 Domain Information Lookup


> I notice the data elements listed in 3.2.4.
> I remember the old .com NIC Handles that were once common when there was a
> monopoly.
> Nowadays, handles to whois contacts are difficult to implement across
> registries,
> and even within registries in a distributed whois model.
> But I was thinking that new registries in the future could use
> the domain name itself as a sort of NIC handle.  
> In the RRP registry we are implementing the whois information
> could be nothing more than another domain name, in effect,
> a pointer to other whois information. 
> The list of TLDs allowed for the other domain name would be 
> restricted to say gTLDs.  The registrant
> of the other domain name is the registrant of the first domain name.
> For exmaple, with this, you could specify that the registrants for 
> ibm.newTLD and thinkpad.newTLD would be
> the same as the registrant for ibm.com.
> In this way the domain name serves as a "NIC Handle" and
> works across registries.  
> Would the specification preclude this type of thing?
> 
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